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Time and Work is one of the most important topics in General Aptitude and is frequently asked in GATE, PSU, ESE, AE/JE exams. This topic focuses on efficiency, work rate, and time required to complete tasks.
The fundamental idea is:
Work = Time × Efficiency
Where:
If a person completes work in x days:
1 day work = 1/x
If A takes x days and B takes y days:
1 day work = (1/x + 1/y)
If A is twice as efficient as B:
Efficiency ratio = 2 : 1
A can complete a work in 10 days. What is A’s one day work?
1 day work = 1/10
A can do a work in 10 days and B in 20 days. Find time taken together.
1 day work = 1/10 + 1/20 = 3/20
Total time = 20/3 = 6.67 days
A is twice as efficient as B. If B takes 12 days, find time taken by A.
Efficiency ratio = 2 : 1
Time ratio = 1 : 2
A takes = 12/2 = 6 days
A and B together complete work in 8 days. A alone can do it in 12 days. Find B’s time.
A + B = 1/8
A = 1/12
B = (1/8 - 1/12) = (3 - 2)/24 = 1/24
B takes 24 days
Q1. A can do a work in 15 days. B can do it in 10 days. Find time taken together.
1 day work = 1/15 + 1/10 = 1/6
Time = 6 days
Q2. A, B, C can complete work in 6, 8, 12 days respectively. Find combined time.
1 day work = 1/6 + 1/8 + 1/12 = 4/24 + 3/24 + 2/24 = 9/24 = 3/8
Time = 8/3 = 2.67 days
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