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Permutations and Combinations (P&C) is an important topic in General Aptitude and is frequently asked in exams like GATE, PSU, ESE, AE/JE. It helps in solving problems related to arrangements, selections, and counting techniques.
n! = n × (n − 1) × (n − 2) × ... × 1
0! = 1
5! = 5 × 4 × 3 × 2 × 1 = 120
nPr = n! / (n − r)!
Number of ways to arrange 3 items out of 5:
5P3 = 5! / 2! = 60
nCr = n! / [r! (n − r)!]
Number of ways to select 3 items out of 5:
5C3 = 5! / (3! × 2!) = 10
In how many ways can 4 students be selected from 10 students?
Solution:
10C4 = 10! / (4! × 6!) = 210
Answer: 210
In how many ways can 3 books be arranged from 6 different books?
Solution:
6P3 = 6! / 3! = 120
Answer: 120
Find the value of 8C2.
Solution:
8C2 = (8 × 7) / 2 = 28
Answer: 28
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